Question

o trapezio a seguir é isosceles,tem as bases medindo 10 cm e 16 cm e o perimetro igual a 36 cm.qual é a area?

Answer 1

perimetro =x+x+10+16=36         a=B+b).h/2, tenho que achar a medida da
                  2x=36-26                altura
                   2x=10                   
                    x=10/2              
                   x=5                   5²=h²+3²
                                          25=h²+9
                                        h²+9=25
                                       h²=25-9
                                      h²=16
                                       h=√16
                                     h=4
Usando a formula da area
a=B+b).h/2
a=16+10).4/2
a=26.4/2
a=104/2
a=52cm² é a area desse trapezio