o textos das questões de 1 a 4
Soluções para a tarefa
Resposta:
\begin{lgathered}ae = \frac{se}{n} \\ ae = \frac{360°}{8} = 45°\end{lgathered}
ae=
n
se
ae=
8
360°
=45°
\begin{lgathered}ai + ae = 180° \\ ai + 45° = 180° \\ ai = 180° - 45° \\ ai = 135°\end{lgathered}
ai+ae=180°
ai+45°=180°
ai=180°−45°
ai=135°
b)
\begin{lgathered}ae = \frac{se}{n} \\ ae = \frac{360}{7} = 51,42°\end{lgathered}
ae=
n
se
ae=
7
360
=51,42°
\begin{lgathered}ai + ae = 180° \\ ai = 180° - 51,42° \\ ai = 128,58°\end{lgathered}
ai+ae=180°
ai=180°−51,42°
ai=128,58°
c)
\begin{lgathered}ae = \frac{se}{n} \\ ae = \frac{360}{9} = 40°\end{lgathered}
ae=
n
se
ae=
9
360
=40°
\begin{lgathered}ai + ae = 180° \\ ai + 40° = 180° \\ ai = 180° - 40° \\ ai = 140°\end{lgathered}
ai+ae=180°
ai+40°=180°
ai=180°−40°
ai=140°
d)
\begin{lgathered}ae = \frac{se}{n} \\ ae = \frac{360°}{12} = 30°\end{lgathered}
ae=
n
se
ae=
12
360°
=30°
\begin{lgathered}ai + ae = 180° \\ ai + 30° = 180° \\ ai = 180° - 30° \\ ai = 150°\end{lgathered}
ai+ae=180°
ai+30°=180°
ai=180°−30°
ai=150°