Matemática, perguntado por osmannegromonte, 7 meses atrás

O ponto médio do segmento AB determinado pelos A(-1,5) e B(7,4) é: ??​

Soluções para a tarefa

Respondido por PhillDays
6

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\huge\green{\boxed{\rm~~~\gray{P_m}~\pink{=}~\blue{ (3, 4.5) }~~~}}

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\bf\large\green{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad}}

\green{\rm\underline{EXPLICAC_{\!\!\!,}\tilde{A}O\ PASSO{-}A{-}PASSO\ \ \ }}

❄☃ \sf(\gray{+}~\red{cores}~\blue{com}~\pink{o}~\orange{App}~\green{Brainly}) ☘☀

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☺lá, Osman, como tens passado nestes tempos de quarentena⁉ E os estudos à distância, como vão⁉ Espero que bem❗ Acompanhe a resolução abaixo. ✌

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☔ O Ponto Médio entre dois pontos é encontrado como sendo a média aritmética das coordenadas em x e em y de forma que

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\large\red{\boxed{\pink{\boxed{\begin{array}{rcl}&&\\&\orange{\sf P_m = \left(\dfrac{x_a + x_b}{2}, \dfrac{y_a + y_b}{2}\right)}&\\&&\\\end{array}}}}}

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\large\blue{\text{$\sf P_m = \left(\dfrac{-1 + 7}{2}, \dfrac{5+ 4}{2}\right)$}}

\large\blue{\text{$\sf = \left(\dfrac{6}{2}, \dfrac{9}{2}\right)$}}

\large\blue{\text{$\sf = (3, 4.5)$}}

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\huge\green{\boxed{\rm~~~\gray{P_m}~\pink{=}~\blue{ (3, 4.5) }~~~}}

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\setlength{\unitlength}{0.95cm}\begin{picture}(6,5)\thicklines\put(0,0){\vector(1,0){5}}\put(0,0){\vector(0,1){5}}\put(0,0){\vector(-1,0){5}}\put(0,0){\vector(0,-1){5}}\put(5.3,0){x}\put(0.3,5){y}\put(-0.15,0.5){\_\_}\put(-0.15,1){\_\_}\put(-0.15,1.5){\_\_}\put(-0.15,2){\_\_}\put(-0.15,2.5){\_\_}\put(-0.15,3){\_\_}\put(-0.15,3.5){\_\_}\put(-0.15,4){\_\_}\put(-0.15,4.5){\_\_}\put(-0.15,-0.5){\_\_}\put(-0.15,-1){\_\_}\put(-0.15,-1.5){\_\_}\put(-0.15,-2){\_\_}\put(-0.15,-2.5){\_\_}\put(-0.15,-3){\_\_}\put(-0.15,-3.5){\_\_}\put(-0.15,-4){\_\_}\put(-0.15,-4.5){\_\_}\put(0.45,-0.08){$|$}\put(0.95,-0.08){$|$}\put(1.45,-0.08){$|$}\put(1.95,-0.08){$|$}\put(2.45,-0.08){$|$}\put(2.95,-0.08){$|$}\put(3.45,-0.08){$|$}\put(3.95,-0.08){$|$}\put(4.45,-0.08){$|$}\put(-4.55,-0.08){$|$}\put(-4.05,-0.08){$|$}\put(-3.55,-0.08){$|$}\put(-3.05,-0.08){$|$}\put(-2.55,-0.08){$|$}\put(-2.02,-0.08){$|$}\put(-1.55,-0.08){$|$}\put(-1.05,-0.08){$|$}\put(-0.55,-0.08){$|$}\put(-0.50,2.50){\circle*{0.13}}\put(-0.25,2.75){$\sf P_{A}$}\put(3.50,2.0){\circle*{0.13}}\put(3.75,2.25){$\sf P_{B}$}\put(1.50,2.25){\circle*{0.13}}\put(1.75,2.50){$\sf P_{m}$}\bezier{5}(-0.50,2.50)(-0.25,2.50)(0,2.50)\bezier{35}(3.50,2.0)(1.75,2.0)(0,2.0)\bezier{15}(1.50,2.25)(0.75,2.25)(0,2.25)\bezier{25}(-0.50,2.50)(-0.50,1.25)(-0.50,0)\bezier{20}(3.50,2.0)(3.50,1.0)(3.50,0)\bezier{22}(1.50,2.25)(1.50,1.12)(1.50,0)\bezier(-0.50,2.50)(1.50,2.25)(3.50,2.0)\end{picture}

\sf (Esta~imagem~n\tilde{a}o~\acute{e}~visualiz\acute{a}vel~pelo~App~Brainly ☹ )

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\bf\large\red{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}

\bf\Large\blue{Bons\ estudos.}

(\orange{D\acute{u}vidas\ nos\ coment\acute{a}rios}) ☄

\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad }}\LaTeX

❄☃ \sf(\gray{+}~\red{cores}~\blue{com}~\pink{o}~\orange{App}~\green{Brainly}) ☘☀

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\gray{"Absque~sudore~et~labore~nullum~opus~perfectum~est."}

Anexos:

PhillDays: Osman, após o resultado eu inclui um gráfico pra equação do Ponto Médio fazer mais sentido :P
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