O pH de uma soluçao é dado em função da concentração de hidrogenio H+ em mols por litro de solução,pela seguinte expressão:
pH= log(base10)(1/[H+]) ou pH= - log[h+]. Calcule:
a)o pH de uma solução que tem [H+]= 1,0*10elevado a -8;
b)o valor de [H+] para uma solução que tem pH=2
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A) ![pH = -\ log\ [H^+]\\\\ pH = -\ log\ 10^-^8\\\\\ pH = -\ \cdot\ -8\ log\ 10\\\\\ pH = 8\ log\ 10\\\\\ log\ _1_0 10 =1\\\\\ \boxed{pH=8}](https://tex.z-dn.net/?f=pH+%3D+-%5C+log%5C+%5BH%5E%2B%5D%5C%5C%5C%5C+pH+%3D+-%5C+log%5C+10%5E-%5E8%5C%5C%5C%5C%5C+pH+%3D+-%5C+%5Ccdot%5C+-8%5C+log%5C+10%5C%5C%5C%5C%5C+pH+%3D+8%5C+log%5C+10%5C%5C%5C%5C%5C+log%5C+_1_0+10+%3D1%5C%5C%5C%5C%5C+%5Cboxed%7BpH%3D8%7D "pH = -\ log\ [H^+]\\\\ pH = -\ log\ 10^-^8\\\\\ pH = -\ \cdot\ -8\ log\ 10\\\\\ pH = 8\ log\ 10\\\\\ log\ _1_0 10 =1\\\\\ \boxed{pH=8}")
![pH = -\ log\ [H^+]\\\\\ 2 = -\ log\ [H^+]\\\\\ -\ log\ _1_0\ [H^+] = 2\\\\\ \boxed{[H^+] = 10^-^2\ mol/L}](https://tex.z-dn.net/?f=pH+%3D+-%5C+log%5C+%5BH%5E%2B%5D%5C%5C%5C%5C%5C+2+%3D+-%5C+log%5C+%5BH%5E%2B%5D%5C%5C%5C%5C%5C+-%5C+log%5C+_1_0%5C+%5BH%5E%2B%5D+%3D+2%5C%5C%5C%5C%5C+%5Cboxed%7B%5BH%5E%2B%5D+%3D+10%5E-%5E2%5C+mol%2FL%7D "pH = -\ log\ [H^+]\\\\\ 2 = -\ log\ [H^+]\\\\\ -\ log\ _1_0\ [H^+] = 2\\\\\ \boxed{[H^+] = 10^-^2\ mol/L}")
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