Question

o perimetro do triangulo ABC  sabendo que A(1,3) B (7,3) c (7,11) VALE:

A-20

B-26

C-24

D-32

E--24

Answer 1

Dab²=(Xb-Xa)²+(Yb-Ya)²

Dab²=(7-1)²+(3-3)²

Dab²=(6)² = 36

Dab=√36 = 6

 

Dbc²=(Xb-Xa)²+(Yb-Ya)²

Dbc²=(7-7)²+(11-3)²

Dbc²=(8)² =64

Dbc=√64 = 8

 

Dca²=(Xb-Xa)²+(Yb-Ya)²

Dca²=(1-7)²+(3-11)²

Dca²=(-6)²+(-8)²

Dca²=36+64

Dca²=100

Dca=√100 = 10

 

Perimetro do Triangulo ABC = 10 + 8 + 6 = 24