Question

o perimetro de um triangulo equilatero e 18√3 cm calcule a area desse triangulo  

Answer 1

P = 3 l
18√3 = 3.l
l = 6√3 cm

$A = \dfrac{l^2\sqrt{3}}{4} = \dfrac{108\sqrt{3}}{4} = \boxed{27\sqrt{3} \ cm^2}$