Question

O Determine o valor de x nos casos:

Answer 1

Resposta:

$x = 6 \sqrt{2}$

Explicação passo-a-passo:

$\frac{12}{sen45} = \frac{x}{sen30} \\ \\ \frac{12}{ \frac{ \sqrt{2} }{2} } = \frac{x}{ \frac{1}{2} } \\ \\ 12 \times \frac{2}{ \sqrt{2} } = x \times \frac{2}{1} \\ \frac{24}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } = 2x \\ \\ \frac{24 \sqrt{2} }{ \sqrt{4} } = 2x \\ \frac{24 \sqrt{2} }{2} = 2x \\ 12 \sqrt{2} = 2x \\ x = \frac{12 \sqrt{2} }{2} \\ x = 6 \sqrt{2}$