Question

O 4o termo do desenvolvimento de ( x - 2 )6 é

Answer 1

$\mathsf{p+1=4\to~p=4-1=3}\\\mathsf{T_{3+1}={(-1)}^{3}\binom{6}{3}{(-2)}^{3}.{x}^{6-3}}$

$\mathsf{T_{4}=-1.\dfrac{6.5.4}{3.2.1}. (-8).x^{3}}\\\mathsf{T_{4}=160{x}^{3}}$