Question

numa PG ( 2,4,8..........) calcular a razão

Answer 1

A razão de uma P.G é determinada por:

$\mathsf{q=\dfrac{a_n}{a_{n-1}}}\\\\\\\mathsf{q=\dfrac{a_2}{a_1}}\\\\\\\mathsf{q=\frac{4}{2}}\\\\\\\boxed{\boxed{\mathsf{q=2}}}\: \: \checkmark$