Question

Nos triângulos retângulos determine o valor de X

Answer 1

1)

$x^{2} = 12^{2} + 16^{2} \\x^{2} =256 + 144\\x=\sqrt{400} \\x=20$

2)

$x^{2} =12^{2} + 15^{2} \\x^{2} =144+225\\x=\sqrt{369} \\x=3\sqrt{41}$