Question

No desenvolvimento do binómio de Newton (x+y) ^15 qual é o décimo quarto termo?

Answer 1

T_p+1=C_(n,p).a^p.x^(n-p)



p+1=14

p=14-1

p=13


T14=C_(15,13).(y)^13.(X)^(15-13)

T14=C_(15,13).(y^13).(x^2)

T14=15!/(15-13)!(13)!.(y^13).(x^2)

T14=15.14.13!/2!13!.(y^13).(x^2)

T14=210/2.(y^13).(x^2)


T14=105y^13.x^2

espero ter ajudado!

bom dia!

Answer 2

Resposta:

T_p+1=C_(n,p).a^p.x^(n-p)

p+1=14

p=14-1

p=13

T14=C_(15,13).(y)^13.(X)^(15-13)

T14=C_(15,13).(y^13).(x^2)

T14=15!/(15-13)!(13)!.(y^13).(x^2)

T14=15.14.13!/2!13!.(y^13).(x^2)

T14=210/2.(y^13).(x^2)

T14=105y^13.x^2