Question

????? NN sei fazer me ajudem

Answer 1

$\sqrt[3]{ \frac{2^{28}+2^{30}}{10} } = \\ \\ \sqrt[3]{ \frac{2^{28}(1+2^2)}{10} } = \\ \\ \sqrt[3]{ \frac{2^{28}(1+4)}{10} } = \\ \\ \sqrt[3]{ \frac{2^{28}.(\not5)}{\not10_2} } = \\ \\ \sqrt[3]{ \frac{2^{28}}{2} } = \\ \\ \sqrt[3]{2^{28}:2} = \sqrt[3]{2^{28-1}} = \sqrt[3]{2^{27}} =2^9\mapsto letra~~d$

Answer 2

Vamos Lá
$\sqrt[3]{ \frac{2^{28}+2^{30}}{10} }$

primeiro evidenciar $2^{28}$
$2^{28}+2^{30}=1*2^{28}+2^{28}*2^{2} \\ =1*2^{28}+2^{28}*4 \\ =(1+4)2^{28}=5*2^{28}$

agora fica
$\sqrt[3]{ \frac{5*2^{28}}{10} } = \sqrt[3]{ \frac{2^{28}}{2^1} }= \\ = \sqrt[3]{2^{28-1} } \\ \sqrt[3]{2^{27} } } =2^ \frac{27}{3} =2^9$

Resposta Letra D

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