Question

Nas potencias de cima,$3^{x+1} - 3 ^{x}$ , e na parte de baixo $3^{x-1}$

Answer 1

$\frac{3^{x+1}-3^{x}}{3^{x-1}}$

Colocando $3^{x-1}$ em evidência no numerador:

$\frac{3^{x-1}*([3^{x+1}/3^{x-1}]-[3^{x}/3^{x-1}])}{3^{x-1}}\\\\\frac{3^{x-1}*(3^{x+1-x+1}-3^{x-x+1})}{3^{x-1}}\\\\\frac{3^{x-1}*(3^{2}-3^{1})}{3^{x-1}}\\\\\frac{3^{x-1}*(9 - 3)}{3^{x-1}}\\\\\frac{3^{x-1}*6}{3^{x-1}}$

Cortando $3^{x-1}$

$\frac{3^{x-1}*6}{3^{x-1}} = 6$

Letra B)