Matemática, perguntado por larissa4557, 7 meses atrás

nas figuras, a//b//c,calcule o valor de x.
me ajudem por favor ​

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Soluções para a tarefa

Respondido por CyberKirito
1

\boxed{\begin{array}{l}\tt a)~\sf\dfrac{x}{3}=\dfrac{4}{2}\\\sf\dfrac{x}{3}=2\\\sf x=3\cdot2\\\sf x=6\\\tt b)~\sf\dfrac{x}{21}=\dfrac{\diagdown\!\!\!\!4^1}{\diagdown\!\!\!\!\!\!12_3}\\\sf\dfrac{x}{21}=\dfrac{1}{3}\\\sf 3x=21\\\sf x=\dfrac{21}{3}\\\sf x=7\\\tt c)~\sf\dfrac{x}{14}=\dfrac{\diagdown\!\!\!\!9^3}{\diagdown\!\!\!\!\!\!12_4}\\\sf\dfrac{x}{14}=\dfrac{3}{4}\\\sf 4x=42\\\sf x=\dfrac{42\div2}{4\div2}\\\sf x=\dfrac{21}{2}\end{array}}

\large\boxed{\begin{array}{l}\tt d)~\sf\dfrac{x}{9}=\dfrac{\diagdown\!\!\!\!8^2}{\diagdown\!\!\!\!\!\!12_3}\\\sf\dfrac{x}{\diagup\!\!\!\!9_3}=\dfrac{2}{\diagup\!\!\!3_1}\\\sf\dfrac{x}{3}=2\\\sf x=2\cdot3\\\sf x=6\end{array}}

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