Question

nao consigo resolver o problema
y = ײ -8 + 3​

Answer 1

Resposta:

${x}^{2} - 8x + 3 = 0 \\ x = \frac{8 + - \sqrt{ { (- 8)}^{2} - 4(1)(3)} }{2} \\ x = \frac{8 + - \sqrt{64 - 12} }{2} \\ x = \frac{8 + \sqrt{52} }{2} \\ x = \frac{8 + \sqrt{52} }{2} \\ ou \\ x = \frac{8 - \sqrt{52} }{2} \\ x = 4 + \sqrt{52} \: ou \: x = 4 - \sqrt{52}$