Question

Na figura, AO = 6 cm e AÔB = 40º. A área do setor circular é:
a) p cm2
b) 2p cm2
c) 3p cm2
d) 4p cm2
e) 6p cm2

Answer 1

$r=6\ cm\\ \theta=40^o=\frac{2\pi}{9}\ rd\\\\ A=\frac{1}{2}.r^2.\theta\ \to\ A=\frac{1}{2}.6^2.\frac{2\pi}{9}\\\\ A=36.\frac{\pi}{9}\ \to\ \| \ A=4\pi\ cm^2\ \|$

Resposta: Alternativa D.