Question

na figura abaixo, as retas P, Q, R e S são paralelas e AD = 24 cm. determine as medidas dos segmentos AB, BC e CD.

Answer 1

AB/3 = BC/9 = CD/6  = ( AB + BC + CD ) / ( 3 + 9 + 6 ) / 24/18 =4/3 

AB/3  = 4/3
3 * AB  = 3 * 4
3AB = 12
AB = 12/3 = 4 ****

BC/9 = 4/3
3 * BC = 9 * 4 
3BC = 36
BC = 36/3 =  12 ****

CD/6  = 4/3
3 * CD = 6 * 4
3CD = 24
CD = 24/3 = 8 ****

se ajudei não deixe  de  me avaliar com estrelas ***

Answer 2

Resposta:

AB = 4 cm   BC = 12cm   CD = 8cm

Explicação passo-a-passo:

Olá, boa tarde!

$\frac{AB}{24} =\frac{3}{3+9+6} \\\\\frac{AB}{24} =\frac{3}{18} \\\\AB.18=72\\AB=\frac{72}{18} \\\\AB=4$

$\frac{AB}{BC} =\frac{3}{9} \\\\\frac{4}{BC} =\frac{3}{9} \\\\BC.3=4.9\\\\BC.3=36\\\\BC=\frac{36}{3} \\\\BC=12$

$\frac{AB}{CD} =\frac{3}{6} \\\\\frac{4}{CD} =\frac{3}{6} \\\\CD.3=4.6\\\\CD.3=24\\\\CD=\frac{24}{3} \\\\CD=8$

Espero ter ajudado!