na figura a//b//c//calcule o valor de x?
Anexos:
Soluções para a tarefa
Respondido por
1
Boa noite Amandinha!
Solução!
![\dfrac{x-5}{x+1}= \dfrac{6}{24}\\\\\\\
\dfrac{x-5}{x+1}= \dfrac{1 }{4}\\\\\\\
4(x-5)=1(x+1)\\\\\\
4x-20=x+1\\\\\\
4x-x=1+20\\\\\\
3x=21\\\\\
x= \dfrac{21}{3}\\\\\\\
\boxed{x=7}](https://tex.z-dn.net/?f=+%5Cdfrac%7Bx-5%7D%7Bx%2B1%7D%3D+%5Cdfrac%7B6%7D%7B24%7D%5C%5C%5C%5C%5C%5C%5C%0A%0A++%5Cdfrac%7Bx-5%7D%7Bx%2B1%7D%3D+%5Cdfrac%7B1+%7D%7B4%7D%5C%5C%5C%5C%5C%5C%5C%0A4%28x-5%29%3D1%28x%2B1%29%5C%5C%5C%5C%5C%5C%0A4x-20%3Dx%2B1%5C%5C%5C%5C%5C%5C%0A4x-x%3D1%2B20%5C%5C%5C%5C%5C%5C%0A%0A3x%3D21%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B21%7D%7B3%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Bx%3D7%7D+ "\dfrac{x-5}{x+1}= \dfrac{6}{24}\\\\\\\
\dfrac{x-5}{x+1}= \dfrac{1 }{4}\\\\\\\
4(x-5)=1(x+1)\\\\\\
4x-20=x+1\\\\\\
4x-x=1+20\\\\\\
3x=21\\\\\
x= \dfrac{21}{3}\\\\\\\
\boxed{x=7}")
Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
Perguntas interessantes
Ed. Física,
9 meses atrás
Inglês,
9 meses atrás
Matemática,
9 meses atrás
Matemática,
1 ano atrás
Física,
1 ano atrás
Inglês,
1 ano atrás