Question

Na expansão do binômio (x2+ 2)^10 , obtenha o 5° termo e o 8° termo

Answer 1

(x² + 2)^10

$T_5 = \binom{10}{4}.(x^2)^{10 - 4}.2^4 \\ \\ T_5 = 210.x^{12}.16 = 6720x^{12}$

$T_8 = \binom{10}{8}.(x^2)^{10 - 8}.2^8 \\ \\ T_8 = 45.x^4.256 = 11520x^4$