Matemática, perguntado por melquezedek16, 5 meses atrás

(n)-3x+3y-3=0 e (s)3x-3y+1=0​

Soluções para a tarefa

Respondido por 123123divina123
1

Resposta:

(n)-3x+3y-3=0 e (s)3x-3y+1=0​

Let's solve for n.

n−3x+3y−3=0

Step 1: Add 3x to both sides.

n−3x+3y−3+3x=0+3x

n+3y−3=3x

Step 2: Add -3y to both sides.

n+3y−3+−3y=3x+−3y

n−3=3x−3y

Step 3: Add 3 to both sides.

n−3+3=3x−3y+3

Answer:

n=3x−3y+3

Let's solve for s.

s(3)x−3y+1=0

Step 1: Add 3y to both sides.

3sx−3y+1+3y=0+3y

3sx+1=3y

Step 2: Add -1 to both sides.

3sx+1+−1=3y+−1

3sx=3y−1

Step 3: Divide both sides by 3x.

3sx/3x=3y−1/3x

Answer:

s=3y−1/3x

Explicação passo a passo:

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