Question

morrendo com essas duas questões galera!! quem souber me help please!!

Answer 1

3) ∆>0
 $b^2-4ac>0\\4^2-4.2.5k>0\\16-40k>0\\-40k>-16\\k< \frac{16}{40}\\k< \frac{2}{5}$

4) ∆=0
$b^2-4.a.c=0\\(p+5)^2-4.1.36=0\\p^2+10p+25-144=0\\p^2+10p-119=0$
∆=$10^2-4.1.(-119)$
∆=$100+476$
∆=576

$p= \frac{-10+- \sqrt{576} }{2.1}\\p= \frac{-10+-24}{2}\\p'= \frac{-10+24}{2}= \frac{14}{2} =7\\p''= \frac{-10-24}{2}= \frac{-34}{2}=-17$