Question

Mim ajudei a resolver essa questao:
-x^+5x-6=0

Answer 1

$x^2+5x-6=0\\\Delta = 25-4(-6)\\\Delta=25+24=49\\x= \frac{-5\pm \sqrt{49} }{2}\\x'= \frac{-5-7}{2} = \frac{-12}{2} =-6\\x"= \frac{-5+7}{2} = \frac{2}{2} =1$

Answer 2

-x+5x-6=0

4x=0+6

4x=6

x= 6 dividido por 4

x=1,5