Question

medidas dos lados AB, BC, DE, EF​

Answer 1

Resposta:

Explicação passo-a-passo:

Temos que:

i) $AB=d(AB)=\sqrt{(7-1)^{2}+(2-2)^{2}}=\sqrt{6^{2}}=\sqrt{36}=6$

ii) $BC=d(BC)=\sqrt{(4-7)^{2}+(6-2)^{2}}=\sqrt{(3)^{2}+(-4)^{2}}=\sqrt{9+16}=\sqrt{25}=5$

iii) $DE=d(DE)=\sqrt{(-2-(-2))^{2}+(5-2)^{2}}=\sqrt{(-2+2)^{2}+(3)^{2}}=\sqrt{0+9}=3$

iv) $EF=d(EF)=\sqrt{(-6-(-2))^{2}+(5-5)^{2}}=\sqrt{(-6+2)^{2}+0^{2}}=\sqrt{(-4)^{2}}=\sqrt{16}=4$