Question

mediante as explicações anteriores resolva

b) (4×9+12) : (3×5-3)

c) 16 + [(3×6-2) - (10-6;2) + 1

d) (12^2 + 1) : [(54-7^2) + 1^3 - 1

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Answer 1

b)

$(4 \times 9 + 12) \div (3 \times 5 - 3) = (36 + 12) \div (15 - 3) = 48 \div 12 = 4$

c)

$16 + (3 \times 6 - 2) - (10 - 6 \div 2) + 1 = 16 + (18 - 2) - (10 - 3) + 1 = 16 + 16 - 7 = 25$

d)

$( {12}^{2} + 1) \div (54 - {7}^{2} ) + {1}^{3} - 1 = (144 + 1) \div (54 - 49) + 1 - 1 = 145 \div 5 = 29$