me fala a conta também por favor
Anexos:
Soluções para a tarefa
Respondido por
1
Calcule:
![a)\ 64^{ \frac{1}{2}}= \sqrt{64} =8\\
\\b)\ 400^{ \frac{1}{2}}= \sqrt{400} =20\\
\\c)\ ( \frac{16}{25} )^{ \frac{1}{2}}= \sqrt{\frac{16}{25}} =\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\\
\\d)\ 32^{\frac{1}{5}}= \sqrt[5]{32} =2\\
\\e)\ ( \frac{8}{27})^{ \frac{1}{3}}= \sqrt[3]{\frac{8}{27}} =\frac{\sqrt[3]{8}}{\sqrt[3]{27}}=\frac{2}{3}\\](https://tex.z-dn.net/?f=a%29%5C+64%5E%7B+%5Cfrac%7B1%7D%7B2%7D%7D%3D+%5Csqrt%7B64%7D+%3D8%5C%5C%0A%5C%5Cb%29%5C+400%5E%7B+%5Cfrac%7B1%7D%7B2%7D%7D%3D+%5Csqrt%7B400%7D+%3D20%5C%5C%0A%5C%5Cc%29%5C+%28+%5Cfrac%7B16%7D%7B25%7D+%29%5E%7B+%5Cfrac%7B1%7D%7B2%7D%7D%3D+%5Csqrt%7B%5Cfrac%7B16%7D%7B25%7D%7D+%3D%5Cfrac%7B%5Csqrt%7B16%7D%7D%7B%5Csqrt%7B25%7D%7D%3D%5Cfrac%7B4%7D%7B5%7D%5C%5C%0A%5C%5Cd%29%5C+32%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%3D+%5Csqrt%5B5%5D%7B32%7D+%3D2%5C%5C%0A%5C%5Ce%29%5C+%28+%5Cfrac%7B8%7D%7B27%7D%29%5E%7B+%5Cfrac%7B1%7D%7B3%7D%7D%3D+%5Csqrt%5B3%5D%7B%5Cfrac%7B8%7D%7B27%7D%7D+%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B8%7D%7D%7B%5Csqrt%5B3%5D%7B27%7D%7D%3D%5Cfrac%7B2%7D%7B3%7D%5C%5C "a)\ 64^{ \frac{1}{2}}= \sqrt{64} =8\\
\\b)\ 400^{ \frac{1}{2}}= \sqrt{400} =20\\
\\c)\ ( \frac{16}{25} )^{ \frac{1}{2}}= \sqrt{\frac{16}{25}} =\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\\
\\d)\ 32^{\frac{1}{5}}= \sqrt[5]{32} =2\\
\\e)\ ( \frac{8}{27})^{ \frac{1}{3}}= \sqrt[3]{\frac{8}{27}} =\frac{\sqrt[3]{8}}{\sqrt[3]{27}}=\frac{2}{3}\\")
ProfAmaral:
Obrigado.
Perguntas interessantes