Question

me de uma força pessoal

Answer 1

A equação $\frac{3A}{2}+2B=\frac{X}{2}-B$, sendo que $A=\begin{bmatrix}3&4\\1&1\end{bmatrix}$ e $B=\begin{bmatrix}-3&-5\\6&0\end{bmatrix}$

 
$\frac{3A}{2/1}+\frac{2B}{1/2}=\frac{X}{2/1}-\frac{B}{1/2}\\\\3A+4B=X-2B\\\\X=3A+4B+2B\\\\X=3A+6B$

 Segue,

$X=3A+6B\\\\X=3\cdot\begin{bmatrix}3&4\\1&1\end{bmatrix}+6\cdot\begin{bmatrix}-3&-5\\6&0\end{bmatrix}\\\\X=\begin{bmatrix}9&12\\3&3\end{bmatrix}+\begin{bmatrix}-18&-30\\36&0\end{bmatrix}\\\\X=\begin{bmatrix}(9-18)&(12-30)\\(3+36)&(3+0)\end{bmatrix}\\\\\boxed{X=\begin{bmatrix}-9&-18\\39&36\end{bmatrix}}$