Question

Me ajudem.
${6}^{3x} = 64 \\ entao \: {6}^{ - x} =$

Answer 1

Boa noite

6^(3x) = 64 

3x*log(6) = log(64) 
3x = log(64)/(log(6))
x = log(64)/3log(6)
x = log(³√64)/log(6)
x = log(4)/log(6) 

6^-x = (1/6)^x 

(1/6)^(log(4)/log(6)) = (1/10)^log(4) = 1/4