Question

Me ajudem!! Resolva equações exponenciais

Answer 1

Resposta:

Explicação passo-a-passo:

A)

$3^X=243\\\\3^X=3^5\\\\\boxed{x=5}$

B)

$9^{X+5}=\sqrt[3]{27} \\\\9^{X+5}=\sqrt[3]{3^3} \\\\9^{X+5}=3^{\frac{3}{3}} \\\\9^{X+5}=3^{1}\\\\(3^2)^{X+5}=3^{1}\\\\(3)^{2X+10}=3^{1}\\\\2X+10=1\\\\2x=-10+1\\\\2x=-9\\\\\boxed{x=-\dfrac{9}{2} }$

Answer 2

Oie, Td Bom?!

A)

$3 {}^{x} = 243$

$3 {}^{x} = 3 {}^{5}$

• Bases iguais, iguale os expoentes.

$x = 5$

B)

$9 {}^{x + 5} = \sqrt[3]{27}$

$9 {}^{x + 5} = \sqrt[3]{3 {}^{3} }$

$9 {}^{x + 5} = 3 {}^{ \frac{3}{3} }$

$9 {}^{2x + 10} = 3 {}^{1}$

• Bases iguais, iguale os expoentes.

$2x + 10 = 1$

$2x = 1 - 10$

$2x = - 9$

$x = - \frac{9}{2}$

Att. Makaveli1996