Question

ME AJUDEM!!!!!!
quanto é
$(40 x^{3} y):(2xy)$

$\frac{4 a^{4}-2 a^{3} + 8a }{2a}$

Answer 1

$(40x^3y):(2xy) \\ \\ = \frac{40x^3y}{2xy} \\ \\ = \frac{40}{2} \frac{x^3y}{xy} \\ \\ =20x^2$


$\frac{4a^4-2a^3+8a}{2a} \\ \\ = \frac{2a(2a^3-a^2+4)}{2a} \\ \\ =2a^3-a^2+4$