Question

Me ajudem PVF :::: (x-1).(2x+3)=0

Answer 1

(x-1).(2x+3)=0
Realizando a distributiva:
2x² + 3x - 2x - 3= 0
2x² + x - 3=0
a= 2 b= 1 c= -3

Δ= 1² - 4.2.(-3)
Δ= 1 + 24
Δ= 25

x= -1 ± √25/ 4
x= -1 ± 5/ 4

x1= -1 + 5/ 4
x1= 4/4
x1= 1

x2= -1 - 5/4
x2= -6/4
x2= -3/2


S= {1, -3/2}

Answer 2

(x - 1).(2x + 3) = 0
x.2x + 3.x - 1.(2x) - 1.3 = 0
2x² + 3x - 2x - 3 = 0
2x² + x - 3 = 0
a = 2; b = 1; c = - 3

Δ = b² - 4ac
Δ = 1² - 4.2.(-3)
Δ = 1 - 8.(-3)
Δ = 1 + 24
Δ = 25

a = 2; b = 1; c = - 3

x =  - b +/- √Δ     =  - 1 +/- √25
      ---------------      ----------------- 
           2a                     2.2

x = - 1 + 5
      ----------  = 4/4 = 1
            4

x = - 1 - 5          - 6  (:2)      - 3
      -----------  = ------       =  -------
            4             4   (:2)        2

R.: x = 1 e x = - 3/2