Question

me ajudem preciso disso p hoje!!!!!

Answer 1

$a)f(0) = ({2})^{0 - 2} = {2}^{ - 2} = (\frac{1}{2})^{2} = \frac{1}{4} \\ b)f(2) = {2}^{2 - 2} = {2}^{0} = 1 \\ c)g(1) = {3}^{1} + 3 = 3 + 3 = 6 \\ d)g(2) = {3}^{2} + 3 = 9 + 3 = 12 \\ e)g( - 1) = {3}^{ - 1} + 3 = (\frac{1}{3})^{1} + 3 = \frac{1}{3} + 3 = \frac{1 + 9}{3} = \frac{10}{3}$