Question

Me ajudem preciso das respostas urgente.

Answer 1

a) x^2=3^2 +4^2
x^2=9+16
x^2=25
x=raiz de 25
x=5

b)13^2=5^2+x^2
169=25+x^2
169-25=x^2
x^2=144
x=raiz de 144
x=12

c)x^2=15^2+8^2
x^2=225+64
x^2=289
x=raiz de 289
x=17

d)4^2=3^2+x^2
16=9+x^2
x^2=7
x=raiz quadrada de 7

Answer 2

Teorema de Pitágoras, a²=b²+c²
a) x²= 3²+4² => x²= 9+16 => x²= $\sqrt{25}$ => x= 5
b) 13²= 5²+x² => 169=25+x² => x= $\sqrt{144}$  => x= 12
c) x²= 8²+15² => x²= 64+225 => $x= \sqrt{289}$ => x= 17
d) 4²=x²+ 3² => 16=x²+9 => x²= 7 => x= $\sqrt{7}$