Question

me ajudem por favor:
${4}^{2} - 10 + ( {2}^{2} - 5) =$
${2}^{5} + { {3}^{3} \div 9 + [ {3}^{2} \times 5 + 3 \times ( {2}^{3} - {5}^{1} )]} =$
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Answer 1

$4 {}^{2} - 10 + (2 {}^{2} - 5)$

$16 - 10 + (4 - 5)$

$6+ ( - 1)$

$\red{5}$

$————————————————$

$2 {}^{5} + { {3}^{3} \div 9 + [ {3}^{2} \times 5 + 3 \times ( {2}^{3} - {5}^{1} )]}$

$32 + 3 {}^{3} \div 3 {}^{2} + [3 {}^{2} \times 5 + 3(8 - 5)]$

$32 + 3 + [3 \times 3(5 + 1)]$

$32 + 3 + [3 \times 3 \times 6]$

$32 + 3 + 54$

$35 + 54$

$\red{89}$

Answer 2

Resposta:

4^2 - 10 + 4 - 5 = 16 + 4 - 10 - 5 = 20 - 15 = 5

2^5 + 3^3/9 + 3^2*5 + 3*(2^3 - 5^1)

32 + 3 + 45 + 3*(8 - 5)

80 + 24 - 15 = 89