Question

Me ajudem por favor com esta conta

Answer 1

(-2)^3 + 5^2 / 2^-1
8 + 25 / 1/2
33 / 1/2

3^0 . \| 144 /6
1 . 12 / 6
12/6
2

-2^2 = -4

33/ 1/2 × 2 -4
33 × 2/1 × 2 - 4
33 × 4 - 4
132 - 4
128

raiz quadrada de 128 =~ 11,31

Answer 2

$\sqrt{( \frac{(-2^{3}) + 5^{2} }{2^{-1} } ) * \frac{ 3^{0} * \sqrt{144} }{6} - 2^{2} } = \\ \sqrt{( \frac{8 + 25}{0.5}) * \frac{1 *12}{6} - 4 } = \sqrt{ \frac{33}{0.5} * 2 -4 } = \\ \sqrt{66 * 2 -4} = \sqrt{132 - 4 } = \sqrt{128} = 11.3137085$