Question

ME AJUDEM POR FAVOR
Aplique as propriedades da potenciação nas questões abaixo e resolva-as:

Answer 1

Explicação passo-a-passo:

a)

$\sf 2^2\cdot2^3\cdot2^5=2^{2+3+5}=2^{10}$

b)

$\sf x^{-2}\cdot x^5\cdot x^3=x^{-2+5+3}=x^6$

c)

$\sf 2^7\div2^5=2^{7-5}=2^2$

d)

$\sf 7^{-7}\div7^{5}=7^{-7-5}=7^{-12}$

e)

$\sf (3^2)^6=3^{2\cdot6}=3^{12}$

f)

$\sf (9^5)^4=9^{5\cdot4}=9^{20}$

g)

$\sf (n^3)^{-3}=n^{3\cdot(-3)}=n^{-9}$

h)

$\sf (8\cdot10)^4=8^4\cdot10^4$

i)

$\sf (11^3\cdot15^6)^5=11^{3\cdot5}+15^{6\cdot5}=11^{15}\cdot15^{30}$

Answer 2

Oie, Td Bom?!

a)

$= 2 {}^{2} \: . \: 2 {}^{3} \: . \: 2 {}^{5}$

$= 2 {}^{2 + 3 + 5}$

$= 2 {}^{10}$

b)

$= x {}^{ - 2} \: . \: x {}^{5} \: . \: x {}^{3}$

$= x {}^{ - 2 + 5 + 3}$

$= x {}^{6}$

c)

$= 2 {}^{7} \div 2 {}^{5}$

$= 2 {}^{7 - 5}$

$= 2 {}^{2}$

d)

$= 7 {}^{ -7 } \div 7 {}^{5}$

$= 7 {}^{ - 7 - 5}$

$= 7 {}^{ - 12}$

e)

$= (3 {}^{2} ) {}^{6}$

$= 3 {}^{2 \: . \: 6}$

$= 3 {}^{12}$

f)

$= (9 {}^{5} ) {}^{4}$

$= 9 {}^{5 \: . \: 4}$

$= 9 {}^{20}$

g)

$= (n {}^{3} ) {}^{ - 3}$

$= n {}^{3 \: . \: ( - 3)}$

$= n {}^{ - 9}$

h)

$= (8 \: . \: 10) {}^{4}$

$= 8{}^{4} \: . \: 10 {}^{4}$

i)

$= (11 {}^{3} \: . \: 15 {}^{6} ) {}^{5}$

$= 11 {}^{3 \: . \: 5} + 15 {}^{6 \: . \: 5}$

$= 11 {}^{15} + 15 {}^{30}$

Att. Makaveli1996