Matemática, perguntado por mmoreiradeoliveira27, 3 meses atrás

Me ajudem por favor!!!
a) 1/4 + 2/4 – 3/12 b) -6/7 – 1/5 – 8/10 c) 2/3 – 2/3 + 4/5 – 1/4 d) –2/3 –2/3 –4/5 +1/4
Resolvam com as contas!!

Soluções para a tarefa

Respondido por henrique25cordeiro
1

Resposta:

a) 6/12 ou 1/2

b)-130/70 ou -13/7

c) 11/20

d) -113/60

Cálculos:

a) 1/4+2/4-3/12 =

(12÷4×1)+(12÷4×2)-(12÷12×3)/12 =

(3×1)+(3×2)-(1×3)/12 =

3+6-3/12 =

6/12

= 6÷2/12÷2 = 3/6 = 3÷3/6÷3 = 1/2

b) -6/7-1/5-8/10 =

-(70÷7×6)-(70÷5×1)-(70÷10×8)/70 =

-(10×6)-(14×1)-(7×8)/70 =

-60-14-56/70 =

-74-56/70 =

-130/70

= -130÷2/70÷2 = -65/35 = -65÷5/35÷5 = -13/7

c) 2/3-2/3+4/5-1/4 =

4/5-1/4 =

(20÷5×4)-(20÷4×1)/20 =

(4×4)-(5×1)/20 =

16-5/20 =

11/20

d) -2/3-2/3-4/5+1/4 =

-(60÷3×2)-(60÷3×2)-(60÷5×4)+(60÷4×1)/60 =

-(20×2)-(20×2)-(12×4)+(15×1)/60 =

-40-40-48+15/60 =

-80-48+15/60 =

-128+15/60 =

-113/60 =

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