Question

Me ajudem por favor.

Answer 1

$20 {x}^{3} + 2 {x}^{2} {y}^{5}$

$20 {( - 4)}^{3} + 2 {( - 4)}^{2} {(2)}^{5}$

$20( - 64) + 2(16)(32)$

$1280 + 2(512)$

$1280 + 1024 = 2304$