Question

ME AJUDEM POR FAVOR!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!​

Answer 1

$\frac{1 + \frac{1}{1-\frac{1}{5} } }{-1+ \frac{3}{1+\frac{1}{5} } } = \frac{1 + \frac{1}{\frac{5-1}{5} } }{-1+ \frac{3}{\frac{5+1}{5} } } = \frac{1 + \frac{1}{\frac{4}{5} } }{-1+ \frac{3}{\frac{6}{5} } }= \frac{1+1.\frac{5}{4} }{-1+3.\frac{5}{6} } = \frac{1+ \frac{5}{4} }{ -1+\frac{15}{6} } = \frac{\frac{4+5}{4} }{\frac{-6+15}{6} } =\frac{\frac{9}{4} }{\frac{9}{6} } = \frac{9}{4} .\frac{6}{9} = \frac{54:3}{36:3} =\frac{18:6}{12:6} = \frac{3}{2}$