Question

me ajudem por favor!!!​

Answer 1

f(×) (a×+200)/(b×+c)

pelo gráfico ,temos.

×=0--->f(0)=20--->20=a*0+200/(b*0+c)20=200/c--->c=200/20--->c=10

×=6--> f(6)=50--->50=(a*6+200)/(b*6+10)--50=)6a+200)/(6b+10)--->300b+500=6a+200--->a=50b+50. Equação l

×=10f(10)=60--->60=(a*10+200)/(b*10+10)--->6=(a+20)/(10b+10)---->a=60b+40. Equação ll

ll-l --->60b+40=50b+50-->10b=10--->b=1---a=100

f(×)=(100×+200)/(×+10)