Question

Me ajudem, por favor!!! ​

Answer 1

a)

${3}^{ - 1} + \frac{2}{3} = \frac{1}{3} + \frac{2}{3} = \frac{1 + 2}{3} = \frac{3}{3} = 1$

b)

${3}^{ - 1} \times 9 = \frac{1}{3} \times \frac{9}{1} = \frac{9}{3} = 3$

c)

${7}^{ - 2} \times 49 = ( { \frac{1}{7}) }^{2} \times \frac{49}{1} = \frac{1}{49} \times \frac{49}{1} = \frac{49}{49} = 1$

d)

${6}^{ - 2} + \frac{35}{36} = ( { \frac{1}{6} )}^{2} + \frac{35}{36} = \frac{1}{36} + \frac{35}{36} = \frac{35 + 1}{36} = \frac{36}{36} = 1$