Question

ME AJUDEM,PLEASE
resolva o sistema usando o método de substituição
{x-y=8
4x+y=3

Answer 1

$x-y = 8\\\\-y = 8-x\\\\y= -(8-x)\\\\y=(-8+x)$

substituindo o valor de y na segunda equaçao
$4x+y = 3\\\\4x -8+x = 3\\\\5x-8 = 3\\\\ 5x = 3+8\\\\x= \frac{11}{5}$

agora achando o valor de y
$y= -8 + x\\\\y= -8 + \frac{11}{5} \\\\y= \frac{-8*5 +11}{5} \\\\y= \frac{-40+11}{5}\\\\y= \frac{-29}{5}$