Question

me ajudem pfvv
a)3 (x-5)=6
b)2 (3×_ 10)=x
c)5 (×+3)=4 (×_1)
d)4 (2×_1)=2 (3)
Bgdd❤

Answer 1

Oi

a) 3(x-5) = 6

3x - 15 = 6

3x = 6 + 15

3x =  21

x = 21/3 ÷ 3

x = 7

b) 2(3x-10)= x

6x - 20 = x

6x - x = 20

5x = 20

x = 20/5 ÷ 5

x = 4

c) 5(x+3) = 4(x-1)

5x + 15 = 4x - 4

5x - 4x = -4 - 15

x = -19

d) 4(2x-1)= 2(3)

8x - 4 = 6

8x = 6 + 4

8x = 10

x = 10/8 ÷ 2

x = 5/4

Bons estudos

Answer 2

Olá!

$a)3 (x-5)=6 \\ 3x - 15 = 6 \\ 3x = 6 + 15 \\ 3x = 21 \\ x = \frac{21}{3} \\ x = 7$

$b)2 (3x - 10)=x \\ 6x - 20 = x \\ 6x - x = 20 \\ 5x = 20 \\ x = \frac{20}{5} \\ x = 4$

$c)5 (x+3)=4 (x - 1) \\ 5x + 15 = 4x - 4 \\ 5x - 4x = - 4 - 15 \\ x = - 19$

$d)4 (2x - 1)=2 (3) \\ 8x - 4 = 6 \\ 8x = 6 + 4 \\ 8x = 10 \\ x = \frac{10}{8} ÷ 2$

x = 5/4


Espero ter ajudado. Bons estudos!!