Question

Me ajudem pfvr, fórmula de bhaskara​

Answer 1

Explicação passo-a-passo:

Fórmula de Bhaskara:

x = -b ± √∆\2.a

∆ = b² - 4.a.c

a) 2x² + x - 3 = 0

a = 2

b = 1

c = -3

∆ = 1² - 4.2.(-3)

∆ = 1 + 24

∆ = 25

x = -1 ± √25/2.2

x = -1 ± 5/4

x' = -1 + 5/4

x' = 4/4

x' = 1

x" = -1 - 5/4

x" = -6/4

x" = -3/2

S = {1, -3/2}

b) -3x² + x - 3 = 0

a = -3

b = 1

c = -3

∆ = 1² - 4.(-3).(-3)

∆ = 1 - 36

∆ = -35

S = ∅

c) 3x² + x - 1 = 0

a = 3

b = 1

c = -1

∆ = 1² - 4.3.1

∆ = 1 - 12

∆ = -11

S = ∅

d) -2x² + 3x + 9 = 0

a = -2

b = 3

c = 9

∆ = 3² - 4.(-2).9

∆ = 9 + 72

∆ = 81

x = -3 ± √81/2.(-2)

x = -3 ± 9/-4

x' = -3 + 9/-4

x' = 6/-4

x' = 3/-2

x" = -3 - 9/-4

x" = -12/-4

x" = 3

S = {3, 3/-2}

e) 4x² + 8x + 6 = 0

a = 4

b = 8

c = 6

∆ = 8² - 4.4.6

∆ = 64 - 96

∆ = -32

S = ∅

f) x² - 4x - 5 = 0

a = 1

b = -4

c = -5

∆ = (-4)² - 4.1.(-5)

∆ = 16 + 20

∆ = 36

x = -(-4) ± √36/2.1

x = 4 ± 6/2

x' = 4 + 6/2

x' = 10/2

x' = 5

x" = 4 - 6/2

x" = -2/2

x" = -1

S = {5, -1}