Question

me ajudem pfv !!!!

pelo menos a primeira, agradeço. ​

Answer 1

D)

$\sqrt[4]{2 {}^{7} \times 3 {}^{5} \times 5 {}^{4} } = \\ 2 {}^{7} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 128 \\ \sqrt[4]{128 \times {3}^{5} \times 5 {}^{4} } = \sqrt[4]{2 {}^{4} \times 8 \times {3}^{5} \times {3}^{4} } \\ \sqrt[4]{ {2}^{4} \times 8\times {3}^{4} \times 3 \times {5}^{4} } = \sqrt[4]{ {2}^{4} } \sqrt[4]{ {3}^{4} } \sqrt[4]{5 {}^{4} } \sqrt[4]{8 \times 3} = \\ 2 \sqrt[4]{ {3}^{4} } \sqrt[4]{ {5}^{4} } \sqrt[4]{8 \times 3} = 2 \times 3 \sqrt[4]{5 {}^{4} } \sqrt[4]{8 \times 3} = \\ 2 \times 3 \times 5 \sqrt[4]{8 \times 3} = 30 \sqrt[4]{24}$

E)

$\sqrt[3]{162} = \sqrt[3]{ {3}^{3} \times 6 } = \sqrt[3]{ {3}^{3} } \sqrt[3]{6} = \\ 3 \sqrt[3]{6}$

F)

$\sqrt[6]{3 {}^{3} \times 4 {}^{12} } = \sqrt[6]{27 \times 4 {}^{12} } = \\ 4 {}^{2} \times \sqrt[6]{27} = 16 \sqrt[6]{3 {}^{3} } = \\ 16 \sqrt{3}$

Espero ter ajudado :)