Question

Me ajudem pfv, equação exponencial:

Answer 1

$(2^{2})^{x+1} -9\cdot2^{x}+2=0\\ 4\cdot(2^{x})^{2} -9\cdot2^{x}+2=0$

$2^{x} =u$

4u² -9u +2 = 0

$\boxed{\mathsf{\Delta=b^2-4ac}}$

(-9)² -4 * 4 * 2

81 -32

49 → 7²

$\boxed{\mathsf{u=\frac{-b\pm\sqrt{\Delta}}{2a}}}}$

[-(-9) ± √7²]/(2 * 4)

9 ± 7/8

$2^{x} =u$

u' = 16/8

2ˣ = 2

x' = 1

u'' = 2/8

2ˣ = (1/4)

2ˣ = 2⁻²

x'' = -2

{1 , -2}