Question

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Answer 1

$+ \left \{ {{x+3y=16} \atop {2x-3y=6}} \right \\ \\ 3x=22 \\ x= \frac{22}{3} \\ \\ \frac{22}{3}+3y=16 \\ \\ 3y=16- \frac{22}{3}= \frac{26}{3} \\ \\ y= \frac{ \frac{26}{3} }{3}= \frac{26}{3}.3=26 \\ \\ \\ x= \frac{22}{3} \\ \\ y=26$