Question

me ajudem pf
a)-x^2-x+30=0
b)(X-3)^2=-2X^2

Answer 1

a) -x² -x +30=0
Δ = b² -4.a.c
Δ = (-1)² -4. (-1) . 30
Δ = 1 + 120
Δ = 121

x = -b+- √Δ/2.a
x = -(-1)+-√121/2.(-1)
x = 1 +-11/-2
x1 = 1+11/-2
x1 = 12/-2 
x1 = -6

x2 = 1 - 11/-2
x2 = -10/-2
x2 = 5

b)(x-3)²=-2x²
x-3 . x-3 = -2x²
x² -3x -3x + 9 = -2x²
 x² + 2x² -6x +9 = 0
3x² -6x +9=0

Δ= b²-4.a.c
Δ= (-6)² -4.3.9
Δ= 36- 108
Δ= -72

Não existe raiz real   

Answer 2

Δ=b^2-4ac
Δ= 1-4×(-1)×30
Δ= 1+120
Δ=121

x1=-b+√Δ/2a
x1= 1+11/-2
x1= 12/-2
x1= -6

x2=-b-11/2a
x2=1-11/-2
x2=-10/-2
x2= 5