Question

 me ajudem pf  6x ²+5x-4=0

Answer 1

6x ²+5x-4=0 ~> a = 6 , b = 5 , c = -4

Δ = b² - 4ac
Δ = 5² - 4.6.(-4)
Δ = 25 - (-96)
Δ = 121

x = -b ± √Δ
         2a

x = -5 ± √121
         2.6

x = -5 ± 11
         12

x' = -5 + 11 = 6 = 2 = 1          x" = -5 - 11 = -16 = -8 = -4
         12       12   4    2                    12        12     6     3

Answer 2

$6x^2+5x-4=0\\ \\\Delta=5^2-4.6.(-4)\\\Delta=25+96\\\Delta=121$

$x= \frac{-5\pm \sqrt{121} }{2.6}$

$x= \frac{-5\pm11}{12}$

$\boxed{x'= \frac{-16}{12} ~\to~- \frac{3}{4} }$

$\boxed{x''= \frac{6}{12} ~\to~ \frac{1}{2} }$