Question

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Numa  P.G., tem-se: a1= 1, q=√3. Calcule a7.

Answer 1

$a_n=a_1\cdot q^{n-1}$

$a_1=1$

$q=\sqrt{3}$

$a_7=1\cdot(\sqrt{3})^{6}$

$a_7=\sqrt{3^6}$

$a_7=\sqrt{(3^3)^2}$

$a_7=3^3$

$a_7=27$