Question

Me ajudem NESSE PFVRRR

Answer 1

l)

$\sqrt{ \frac{4}{625} } = \frac{ \sqrt{4} }{ \sqrt{625} } = \frac{2}{25}$

m)

$\sqrt{ \frac{225}{256} } = \frac{ \sqrt{225} }{ \sqrt{256} } = \frac{15}{16}$

n)

$\sqrt{ \frac{1024}{100} } = \frac{ \sqrt{1024} }{ \sqrt{100} } = \frac{32}{10} = \frac{16}{5}$

f)

$\sqrt[3]{ - 125} = - 5$

g)

$\sqrt[5]{ - 32} = - 2$